1X^2+12x=17

Solution for 1X^2+12x=17 equation:

1X^2+12X=17

We move all terms to the left:

1X^2+12X-(17)=0

We add all the numbers together, and all the variables

X^2+12X-17=0

a = 1; b = 12; c = -17;
Δ = b2-4ac
Δ = 122-4·1·(-17)
Δ = 212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{212}=\sqrt{4*53}=\sqrt{4}*\sqrt{53}=2\sqrt{53}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{53}}{2*1}=\frac{-12-2\sqrt{53}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{53}}{2*1}=\frac{-12+2\sqrt{53}}{2}
$